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In probability theory the hypoexponential distribution or the generalized Erlang distribution is a continuous distribution, that has found use in the same fields as the Erlang distribution, such as queueing theory, teletraffic engineering and more generally in stochastic processes. It is called the hypoexponential distribution as it has a coefficient of…
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distribution displaystyle lambda phase-type exponential hypoexponential probability dots distributions stochastic coefficient variation parameters general case boldsymbol theta 1- mean see
| Subject | Predicate | Object | Confidence | Src |
|---|---|---|---|---|
| Hypoexponential distribution | CDF | Expressed as a phase-type distribution 1 − α e x Θ 1 {\displaystyle 1-{\boldsymbol {\alpha }}e^{x\Theta }{\boldsymbol {1}}} | 1.00 | infobox |
| Hypoexponential distribution | CF | α ( i t I − Θ ) − 1 Θ 1 {\displaystyle {\boldsymbol {\alpha }}(itI-\Theta )^{-1}\Theta \mathbf {1} } | 1.00 | infobox |
| Hypoexponential distribution | Excess kurtosis | no simple closed form | 1.00 | infobox |
| Hypoexponential distribution | Mean | ∑ i = 1 k 1 / λ i {\displaystyle \sum _{i=1}^{k}1/\lambda _{i}\,} | 1.00 | infobox |
| Hypoexponential distribution | Median | General closed form does not exist | 1.00 | infobox |
| Hypoexponential distribution | MGF | α ( t I − Θ ) − 1 Θ 1 {\displaystyle {\boldsymbol {\alpha }}(tI-\Theta )^{-1}\Theta \mathbf {1} } | 1.00 | infobox |
| Hypoexponential distribution | Mode | ( k − 1 ) / λ {\displaystyle (k-1)/\lambda } if λ k = λ {\displaystyle \lambda _{k}=\lambda } , for all k | 1.00 | infobox |
| Hypoexponential distribution | Parameters | λ 1 , … , λ k > 0 {\displaystyle \lambda _{1},\dots ,\lambda _{k}>0\,} rates (real) | 1.00 | infobox |
| Hypoexponential distribution | Expressed as a phase-type distribution − α e x Θ Θ 1 {\displaystyle -{\boldsymbol {\alpha }}e^{x\Theta }\Theta {\boldsymbol {1}}} Has no other simple form; see article for details | 1.00 | infobox | |
| Hypoexponential distribution | Skewness | 2 ( ∑ i = 1 k 1 / λ i 3 ) / ( ∑ i = 1 k 1 / λ i 2 ) 3 / 2 {\displaystyle 2(\sum _{i=1}^{k}1/\lambda _{i}^{3})/(\sum _{i=1}^{k}1/\lambda _{i}^{2})^{3/2}} | 1.00 | infobox |
| Hypoexponential distribution | Support | x ∈ [ 0 ; ∞ ) {\displaystyle x\in [0;\infty )\!} | 1.00 | infobox |
| Hypoexponential distribution | Variance | ∑ i = 1 k 1 / λ i 2 {\displaystyle \sum _{i=1}^{k}1/\lambda _{i}^{2}} | 1.00 | infobox |
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